Path Compression and Union by Rank

Path compression shortens parent chains during find, while union by rank attaches a shallower tree below a deeper one. This guide works through a concrete example and the trade-offs to remember.

By Rishipal Singh · · 2 min read

Path Compression and Union by Rank: a topic-specific visual connecting the core idea, a worked example, and a common edge case.
Visual guide: Path Compression and Union by Rank: a topic-specific visual connecting the core idea, a worked example, and a common edge case.

Path compression shortens parent chains during find, while union by rank attaches a shallower tree below a deeper one.

How to reason about it

Start by identifying the state the method maintains and the operation that changes it. Then trace one small input by hand. This separates the invariant that makes the method correct from implementation details such as arrays, pointers, counters, or protocol messages.

Worked example

If find(x) follows x-p-q-root, compression redirects x and p closer to root for future queries.

Write down the state before and after each step. For a larger input, repeat the same transition rather than guessing from the final output. That habit makes edge cases visible and gives you a concrete basis for testing.

Trade-offs and common mistakes

The near-constant amortized bound applies to sequences of operations, not to a promise that every single operation is O(1).'

Choose this technique when its assumptions match the problem. State those assumptions explicitly, test an empty or boundary input, and compare the cost of the operation you perform most often with the memory or setup cost it introduces.

Takeaway

Path Compression and Union by Rank becomes easier to use once its invariant, input assumptions, and failure cases are clear. A small worked example is a useful first test; measurements and proofs should follow when the system grows.

Practice: reason about path compression and union by rank

Using the worked example in this guide, what is the key step or invariant to check?

Reveal the explanation

If find(x) follows x-p-q-root, compression redirects x and p closer to root for future queries. The near-constant amortized bound applies to sequences of operations, not to a promise that every single operation is O(1).'